2) 2/3 ²Log 8 - 3/2 ²Log 16 + 1/2 ²Log 32 =
Penjelasan dengan langkah-langkah:
Nomor 1
[tex]\frac{81^{2-x} }{27^{x+3}}[/tex] = [tex]9^{2x}[/tex]
[tex]\frac{3^{4(2-x)} }{3^{3(x+3)} } = 3^{2(2x)}[/tex]
[tex]3^{4(2-x)-3(x+3)}[/tex] = [tex]3^{2(2x)}[/tex]
8-4x-3x-9 = 4x
8-7x-9 = 4x
-1 = 11x
[tex]\frac{-1}{11}[/tex] = x
Nomor 2
[tex]\frac{2}{3}[/tex] ²log 8 - [tex]\frac{3}{2}[/tex] ²log 16 + [tex]\frac{1}{2}[/tex] ²log 32 = [tex]\frac{2}{3}[/tex] ²log [tex]2^{3}[/tex] - [tex]\frac{3}{2}[/tex] ²log 2⁴ + [tex]\frac{1}{2}[/tex] ²log 2⁵
= [tex]\frac{2}{3}[/tex] . 3 ²log 2 - [tex]\frac{3}{2}[/tex]. 4 ²log 2 + [tex]\frac{1}{2}[/tex] . 5 ²log 2
= 2 . 1 - 6 . 1 + [tex]\frac{5}{2}[/tex] . 1
= 2 - 6 + [tex]\frac{5}{2}[/tex]
= [tex]-\frac{3}{2}[/tex]
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